[flang] Check assignment conformance for derived types (#99059)

Derived type assignment checking needs to account for the possibility of
derived assignment. The implementation was checking compile-time
conformance errors only on the path for assignments of intrinsic types.
Add a static array conformance check in the derived type flow once it
has been established that no defined assignment exists.

Fixes https://github.com/llvm/llvm-project/issues/98981.
This commit is contained in:
Peter Klausler 2024-07-18 15:57:32 -07:00 committed by GitHub
parent ef94732b4f
commit 6c09a9bf6c
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3 changed files with 10 additions and 0 deletions

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@ -4533,6 +4533,8 @@ std::optional<ProcedureRef> ArgumentAnalyzer::TryDefinedAssignment() {
!OkLogicalIntegerAssignment(lhsType->category(), rhsType->category())) {
SayNoMatch("ASSIGNMENT(=)", true);
}
} else if (!fatalErrors_) {
CheckAssignmentConformance();
}
return std::nullopt;
}

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@ -35,8 +35,10 @@ subroutine arrayconstructorvalues()
intarray = [integer:: EMPLOYEE (19, "Jack"), 2, 3, 4, 5]
! C7112
!ERROR: Dimension 1 of left-hand side has extent 3, but right-hand side has extent 2
!ERROR: Value in array constructor of type 'INTEGER(4)' could not be converted to the type of the array 'employee'
emparray = (/ EMPLOYEE:: EMPLOYEE(19, "Ganesh"), EMPLOYEE(22, "Omkar"), 19 /)
!ERROR: Dimension 1 of left-hand side has extent 3, but right-hand side has extent 2
!ERROR: Value in array constructor of type 'employeer' could not be converted to the type of the array 'employee'
emparray = (/ EMPLOYEE:: EMPLOYEE(19, "Ganesh"), EMPLOYEE(22, "Ram"),EMPLOYEER("ShriniwasPvtLtd") /)

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@ -1,7 +1,11 @@
! RUN: %python %S/test_errors.py %s %flang_fc1
! Shape conformance checks on assignments
program test
type t
integer n
end type
real :: a0, a1a(2), a1b(3), a2a(2,3), a2b(3,2)
type(t) c(10)
a0 = 0. ! ok
!ERROR: No intrinsic or user-defined ASSIGNMENT(=) matches scalar REAL(4) and rank 1 array of REAL(4)
a0 = [0.]
@ -20,4 +24,6 @@ program test
a2a(1,:) = a1a
!ERROR: Dimension 1 of left-hand side has extent 2, but right-hand side has extent 3
a2a = a2b
!ERROR: Dimension 1 of left-hand side has extent 10, but right-hand side has extent 0
c(1:10) = c(10:1)
end