llvm-project/clang/test/SemaCUDA/autoret-global.cu
Michael Liao 24337db616 [CUDA][HIP] Enable kernel function return type deduction.
Summary:
- Even though only `void` is still accepted as the deduced return type,
  enabling deduction/instantiation on the return type allows more
  consistent coding.

Reviewers: tra, jlebar

Subscribers: cfe-commits, yaxunl

Tags: #clang

Differential Revision: https://reviews.llvm.org/D68031

llvm-svn: 372898
2019-09-25 16:51:45 +00:00

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// RUN: %clang_cc1 -std=c++14 -fsyntax-only -verify %s
#include "Inputs/cuda.h"
template <typename T>
__global__ T foo() {
// expected-note@-1 {{kernel function type 'T ()' must have void return type}}
}
void f0() {
foo<void><<<0, 0>>>();
foo<int><<<0, 0>>>();
// expected-error@-1 {{no matching function for call to 'foo'}}
}
__global__ auto f1() {
}
__global__ auto f2(int x) {
return x + 1;
// expected-error@-2 {{kernel function type 'auto (int)' must have void return type}}
}
template <bool Cond, typename T = void> struct enable_if { typedef T type; };
template <typename T> struct enable_if<false, T> {};
template <int N>
__global__
auto bar() -> typename enable_if<N == 1>::type {
// expected-note@-1 {{requirement '3 == 1' was not satisfied [with N = 3]}}
}
template <int N>
__global__
auto bar() -> typename enable_if<N == 2>::type {
// expected-note@-1 {{requirement '3 == 2' was not satisfied [with N = 3]}}
}
void f3() {
bar<1><<<0, 0>>>();
bar<2><<<0, 0>>>();
bar<3><<<0, 0>>>();
// expected-error@-1 {{no matching function for call to 'bar'}}
}