llvm-project/clang/test/CodeGenCXX/cxx1z-constexpr-if.cpp
Ismail Pazarbasi 4a00774e59 Try contextually converting condition of constexpr if to Boolean value
Summary:
C++1z 6.4.1/p2:
 If the if statement is of the form if constexpr, the value of the
 condition shall be a contextually converted constant expression of type
 bool [...]
C++1z 5.20/p4:
 [...] A contextually converted constant expression of type bool is an
 expression, contextually converted to bool (Clause4), where the
 converted expression is a constant expression and the conversion
 sequence contains only the conversions above. [...]

Contextually converting result of an expression `e` to a Boolean value
requires `bool t(e)` to be well-formed.

An explicit conversion function is only considered as a user-defined
conversion for direct-initialization, which is essentially what
//contextually converted to bool// requires.

Also, fixes PR28470.

Reviewers: rsmith

Subscribers: cfe-commits

Differential Revision: https://reviews.llvm.org/D24158

llvm-svn: 280838
2016-09-07 18:24:54 +00:00

35 lines
666 B
C++

// RUN: %clang_cc1 -std=c++1z %s -emit-llvm -o - | FileCheck %s --implicit-check-not=should_not_be_used
void should_be_used_1();
void should_be_used_2();
void should_be_used_3();
void should_not_be_used();
struct A {
constexpr explicit operator bool() const {
return true;
}
};
void f() {
if constexpr (false)
should_not_be_used();
else
should_be_used_1();
if constexpr (true || ({ label: false; }))
should_be_used_2();
else {
goto foo;
foo: should_not_be_used();
}
if constexpr (A())
should_be_used_3();
else
should_not_be_used();
}
// CHECK: should_be_used_1
// CHECK: should_be_used_2
// CHECK: should_be_used_3