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variable that has regiser constraint "r" is not 64-bit. General register operands are output using 64-bit "x" register names, regardless of the size of the variable, unless the asm operand is prefixed with the "%w" modifier. This surprises and confuses many users who aren't familiar with aarch64 inline assembly rules. With this commit, a note and fixit hint are printed which tell the users that they need modifier "%w" in order to output a "w" register instead of an "x" register. <rdar://problem/12764785> llvm-svn: 216260
9 lines
394 B
C
9 lines
394 B
C
// RUN: %clang_cc1 -triple arm64-apple-macosx10.8.0 -fsyntax-only -verify %s
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unsigned t, r, *p;
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int foo (void) {
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__asm__ __volatile__( "stxr %w[_t], %[_r], [%[_p]]" : [_t] "=&r" (t) : [_p] "p" (p), [_r] "r" (r) : "memory"); // expected-warning{{value size does not match register size specified by the constraint and modifier}} expected-note {{use constraint modifier "w"}}
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return 1;
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}
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